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 One competition in Croatia
Сообщение12.11.2019, 10:35 


01/08/19
103
Let $A_{1},A_{2},\ldots,A_{2015}$ be vertices of a polygon. Determine the point $T$ in the plane of the polygon so that the sum:$$|A_{1}T|+|A_{2}T|+\ldots+|A_{2015}T|$$be the smallest.

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 Re: One competition in Croatia
Сообщение12.11.2019, 10:49 


05/09/16
12110
for $n=3$:
\Изображение
for $n=2015$, one just needs to punch additional $2012$ holes...

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 Re: One competition in Croatia
Сообщение12.11.2019, 13:43 


05/09/16
12110
add: There's no closed-form expression for $T$, unless $A_i$ of some special type (for example, vertices of regular polygon)

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 Re: One competition in Croatia
Сообщение12.11.2019, 16:05 
Аватара пользователя


31/08/17
2116
squares are missed i guess

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 Re: One competition in Croatia
Сообщение12.11.2019, 16:26 


10/03/16
4444
Aeroport
rsoldo в сообщении #1425478 писал(а):
$|A_{1}T|$


What is it? Is this module of a scalar product ($A$ and $T$ are 2D-vectors, right?)

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 Re: One competition in Croatia
Сообщение12.11.2019, 16:44 


01/08/19
103
Distance from $A_{1}$ to $T$.

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 Re: One competition in Croatia
Сообщение12.11.2019, 18:19 


10/03/16
4444
Aeroport
rsoldo
Oook

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 Re: One competition in Croatia
Сообщение05.12.2019, 10:51 


01/08/19
103
Hint: complex numbers :-)

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 Re: One competition in Croatia
Сообщение09.12.2019, 13:41 


02/04/18
240
rsoldo в сообщении #1428920 писал(а):
Hint: complex numbers :-)

Complex numbers who?

Basically... Using complex algebra, we just are to find the minimum of complex function $F(z)$, which real part is $\operatorname{Re} F(z)=u(z)=\sum\limits_{i}^{}|z-z_i|$, where $z_i$ are given.

But laplacian of absolute value is its reciprocal, hence it never equals to zero (except for the points about infinity, and we can't talk about minimum there). Thus, it is impossible to find such a real function $v(z)$ so that $\operatorname{Im} F(z)=v(z)$ and $F(z)$ is differentiable at least somewhere.

I don't see if complex algebra made any difference. Worse, maybe - it led to nothing. At least derivation of $f(x,y)=\sum\limits_{i}^{}\sqrt{(x-x_i)^2+(y-y_i)^2}$ gives equations which are numerically solvable.

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 Re: One competition in Croatia
Сообщение10.12.2019, 10:14 
Заслуженный участник
Аватара пользователя


23/07/08
10910
Crna Gora
Wiki, Geometric median:
Цитата:
The geometric median of a discrete set of sample points in a Euclidean space is the point minimizing the sum of distances to the sample points.
...
Despite the geometric median's being an easy-to-understand concept, computing it poses a challenge. The centroid or center of mass, defined similarly to the geometric median as minimizing the sum of the squares of the distances to each point, can be found by a simple formula — its coordinates are the averages of the coordinates of the points — but it has been shown that no explicit formula, nor an exact algorithm involving only arithmetic operations and kth roots, can exist in general for the geometric median. Therefore, only numerical or symbolic approximations to the solution of this problem are possible under this model of computation.

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