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Light, Origin of mass and Physicial Vaccuum
Electron charge, electron mass, photon dissociation energy, has been calculated on the base of heavy vacuum photon model.
In the beginning there was nothing. Absolute nothing. After, God opened the tap and light shone through.
However, this was not ordinary light, but heavy, with wavelength of Lambda (classical electron radius).
Volume of the photon was lambda x lambda x lambda, with electrical constant of epsilonzero and magnetic permeability
of mewzero. This light appears to have properties of a running wave and standing wave, simultaneously.
How is this possible?
You cand find the answer on fig 1 on newcanadianvideo.com , in the "Physical Vacuum".
In a wire, attached to the generator , exists a electromagnetic standing wave.
If you use an ohmmeter and voltmeter at different points of the wire, these devices will display results that appear on
fig 1.
On both ends of the wire, there is no electrical current
(current cannot leak from the standing wave), but the voltage has the same polarity and has maximum.
In the points where current has maximum, voltage has minimum.
In order for the current to circulate, one other point is needed where the voltage has maximum but opposite polarity.
By symmetry, it is clear without voltemeter that the points will be the middle of the wavelength.
All points are immobile (it is a standing wave), only the magnitude of voltage and current changes by harmonic
oscillation with cable inductivity per meter L= labda*mew zero* *(lnR/r)/2*pi and cable capacity per meter
C =2pi*epsilonzero*/lambda*(lnR/r) .These parameters are well known from radio-mechanics. The equivalency scheme is a parallel oscillating circuit.
If I Turn of the generator, then in the wire the oscillation will ceases due to resistance.
A standing wave in a heavy photon will exist for a long period of time , because there is not resistance.
Energy balance is
LII/2= qq/2C where I= q/c, where c is speed of light
q*q*labda*mew zero* *(lnR/r)/2*2*pi*c*c = q*q*lambda*(lnR/r)/2*2pi*epsilonzero
or
c*c = mew zero* epsilonzero
Resonance oscillation is:
1/srL*C= c/lambda
The destruction energy is
E= h*c/4pi*lambda= 1 MeV
If a nearby wave with this energy excites the photon, it was destruct in three parts.
(Due to the 3 capacitor plates of the standing wave)
I determine the capacitor plate charges at the moment of destruction:
h*c/3*4*pi*lambda =q*q/2*lambda/2
q= sr(h*c*epsilonzero/12*pi)
it is charge of electron (e=q).
Post destruction, each of the plates continues to rotate , which corresponds to the electron current.
e*c/2pi*labda/2 with loop inductility pi*mew zero*lambda/2
Electromagnetic energy is exactly energy of rest electron mass .
mcc/2 = (e*e/pi*labda*pi*labda)* pi*mew zero*lambda/2*2 = e*e*mewzero/2*pi* lambda
m=e*e*mewzero/2*pi* lambda
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22.02.2014, 05:46 
too?
