polynomials

[man111]

Consider the polynomials \displaystyle \bf{p(x)} = \prod_{r=0}^{10}\left(x^{2^{k}}+2^k\right). Then Coefficient of x^{2012} in p(x)

[Руст]

$2012=2^{10}+2^9+2^8+2^7+2^6+2^4+2^3+2^2$ (without $2^0,2^1,2^5$). Therefore coefficient is $2^0*2^1*2^5=64$.

[man111]

Thanks pyct.

To pyct would you like to explain it to me. Thanks