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 Inscribed quadrilateral
Сообщение07.10.2012, 20:32 
Аватара пользователя
Quadrilateral $ABCD$ is inscribed in a circle $k$. On $k$ is chosen a point $P$. $K$, $L$, $M$, $N$ are feets of the perpendiculars drawn from $P$ to the lines $AB$, $CD$, $AD$, $BC$ respectively. Prove that $PK.PL=PM.PN$.

(Оффтоп)

It is a very easy problem but it is a beautiful fact.

 
 
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