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 Circle and a middle
Сообщение19.09.2010, 13:28 
Аватара пользователя
PA and PB are tangents to the circle k(O). D is the intersection point of k and the perpendicular BC to PA. OD intersects the segment PA at the point E. F is the intersection point of k and BE. Line through F and D intersects the segment EA at the point Q. Prove that AQ=EQ.

What about that problem?

 
 
 
 Re: Circle and a middle
Сообщение19.09.2010, 22:40 
Аватара пользователя
The problem is easy. Do you want a hint?

 
 
 
 Re: Circle and a middle
Сообщение19.09.2010, 23:13 
Аватара пользователя
Изображение

 
 
 
 Re: Circle and a middle
Сообщение20.09.2010, 23:02 
Аватара пользователя
<EFD=<DAB=1/2<BOD=90-<CDE=<DEC <=> QE^2=QD.QF=AQ^2

Have you ever seen the problem?
Do you like it?
What is it level of difficulty?

 
 
 [ Сообщений: 4 ] 


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