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PA and PB are tangents to the circle k(O). D is the intersection point of k and the perpendicular BC to PA. OD intersects the segment PA at the point E. F is the intersection point of k and BE. Line through F and D intersects the segment EA at the point Q. Prove that AQ=EQ.
What about that problem?
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The problem is easy. Do you want a hint?
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<EFD=<DAB=1/2<BOD=90-<CDE=<DEC <=> QE^2=QD.QF=AQ^2
Have you ever seen the problem? Do you like it? What is it level of difficulty?
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