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Circle and a middle 19.09.2010, 13:28 |
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13/10/07 755 Роман/София, България
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PA and PB are tangents to the circle k(O). D is the intersection point of k and the perpendicular BC to PA. OD intersects the segment PA at the point E. F is the intersection point of k and BE. Line through F and D intersects the segment EA at the point Q. Prove that AQ=EQ.
What about that problem?
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Re: Circle and a middle 19.09.2010, 22:40 |
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13/10/07 755 Роман/София, България
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The problem is easy. Do you want a hint?
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gris |
Re: Circle and a middle 19.09.2010, 23:13 |
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Заслуженный участник |
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13/08/08 14495
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Re: Circle and a middle 20.09.2010, 23:02 |
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13/10/07 755 Роман/София, България
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<EFD=<DAB=1/2<BOD=90-<CDE=<DEC <=> QE^2=QD.QF=AQ^2
Have you ever seen the problem? Do you like it? What is it level of difficulty?
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