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AQ=CD  04.10.2011, 21:38 |
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13/10/07 755 Роман/София, България
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Последний раз редактировалось ins- 04.10.2011, 21:59, всего редактировалось 5 раз(а).
Let PA and PB are tangents from a point P to the circle k. From A is drawn a line that intersects k and the segment PB at the points C and D respectively. From B is drawn a line parallel to CD that intersects k at point E. Q is the intersection point of AD and PE. Prove that AQ=CD.
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ins- |
Re: AQ=CD  05.10.2011, 20:30 |
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13/10/07 755 Роман/София, България
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