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 Planck constant I calculated in" light, Origi
Сообщение27.02.2014, 21:47 
Заблокирован


22/02/14

4
Light, Origin of mass and Physical Vacuum (almost final)

Uvajaemie dami i gospoda
Eto novaya versiya, v kotoroy Bog mne prislal eshe i postoyannuyu Planka

Electron charge, plank constant,electron mass, has been calculated on the base of heavy vacuum photon model.

In the beginning there was nothing: empty space with zero electrical constant and magnetic permeability . After, God
opened the tap and light shone through.
However, this was not ordinary light, but heavy, with wavelength of lambda (classical electron radius). It is rotation
body, of cause , with volume lambda x lambda x lambda, with electrical constant of epsilonzero and magnetic permeability of
mewzero. This light appears to have properties of a running wave and standing wave, simultaneously.

This heavy photon is equivalent to oscillation circuit (capasitor with two plates on the ens of waveleght and
inductance in between). I call it vacuum circuit. Oscillation circuit can carry any frequency, but
only one frequency is resonance, which corresponds to standing wave.
A standing wave in a heavy photon will exist for a long period of time , because there is not resistance in the circuit .
Its circuit resonance frequency.
If a nearby wave with this energy excites the heavy photon, it split two parts.
I know the capacity of heavy photon
C= epsilonzero*pi*lambda* lambda/4 lambda = pi*epsilonzero*lambda/4. Everybody know voltage which cause break of vacuum ( U=8Mev/m)
It is maximum voltage for this current , naturally. Let me calculate maximum charge on capasitor plate.
U=q/C
q=UC=*8000000*8.5*2.5 = 1.7 * 10 in power minus 19
It is electron charge, naturally.

Let me determine electrical energy whith is accumulate in this circuit for one period

E= I*U/2, where I is maximum current. Due to this current charge is shifted on distance lambda/4 two times

I= 2c*e*/lambda


E= 2*e*e*c*/*epsilon0 =e*e*c/epsilon
Its Planck constant , naturally:

E*lambda/2pi*c= 6*10 in power 34


After destruction, each of the plates continues to rotate , which corresponds to the electron current,
e*c/4lambda, with loop inductance , mew zero*lambda ( approximately)

Electromagnetic energy is exactly energy of rest electron mass .


mcc/2 ~ (e*e*c*c/4*labda*4*labda) *mew zero*lambda/*2 = e*e*c*c*mewzero/16*lambda

This is mass of electron naturally

m~ me~ e*e*mewzero/16*lambda
The frequency of the same oscillation circuits is reduced under collisions due to waves beat . It's all easy.
Just image that two collides heavy photons are circuits with mutual inductance. All formulas you find here[1].
Generally, the universe is getting red with age.

http://www.osc.phys.msu.ru/.../4/.../Sv ... ontury.pdf


--
mike lomidze

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 Re: Planck constant I calculated in" light, Origi
Сообщение27.02.2014, 22:54 
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19/03/10
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