ins- |
Difficult problem 22.11.2008, 11:55 |
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13/10/07 755 Роман/София, България
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This is an interesting problem in my opinion. I tried to solve it but without considerable success. A former colleague of mine showed it few years ago. He said that the problem may have a practical application - for example for the spherical mirrors on the roads. I like this problem because it is combination between beauty of the math and its practical use.
It is given a circumference k with center O(xo, yo) and radius R, and a segment AB it is defined by the points - A(x1, y1) and B(x2,y2). Find the locus of all the points M lying on k for which the line OM is an angle bisector of the angle AMB.
It is posted on this forum and there was a trial of solution but I can't understand it.
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xaxa3217 |
22.11.2008, 18:04 |
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30/09/08 99 москва
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if i correctly read, the locus of all points M will be a line (middle perpendicular at AB) and this is obvious, or my english so bad?:)
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ins- |
22.11.2008, 18:21 |
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13/10/07 755 Роман/София, България
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Ok ... let say ... I didn't explain it in a good way.
I want to calculate the coordinates of point M in terms of R, x0, y0, x1, y1, x2, y2.
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